Radical equations

[wildcat1910]

solve radical 4y+1-radical y-2 equals3

 

[tkhunny]

Please read the "Read Before Posting" section. As yo have shown no effort at all, i must assume you just missed it.

Is it \(\displaystyle \sqrt{4y+1}-\sqrt{y-2} = 3\)?

How do you suppose you might get things out from under a square root?

 

[biffboy]

solve radical 4y+1-radical y-2 equals3

I'm letting r stand for radical
Write question as r(4y+1)=3+r(y-2)
Square both sides 4y+1=9+6r(y-2)+y-2
Rearrange 3y-6=6r(y-2)
Divide both sides by 3 y-2=2r(y-2)
Square both sides y^2-4y+4=4y-8 So y^2-8y+12=0 (y-6)(y-2)=0 y=6 or 2
Any time we square both sides in a solution it is best to check the answers fit. Here they both do.

 

[lookagain]

I'm letting r stand for radical
Write question as r(4y+1)=3+r(y-2)
Square both sides 4y+1=9+6r(y-2)+y-2
Rearrange 3y-6=6r(y-2)
Divide both sides by 3 y-2=2r(y-2)
Square both sides y^2-4y+4=4y-8 So y^2-8y+12=0 (y-6)(y-2)=0 y=6 or 2
Any time we square both sides in a solution it is best to check the answers fit. Here they both do.

biffboy,

this site is "Free Math Help," with the emphasis on "help."

tkhunny noted that there was no work shown by the original poster
and gave a prompt/hint.

Any post that follows tkhunny's in this case shouldn't show a completed
solution without some work shown by the poser.

 

[biffboy]

biffboy,

this site is "Free Math Help," with the emphasis on "help."

tkhunny noted that there was no work shown by the original poster
and gave a prompt/hint.

Any post that follows tkhunny's in this case shouldn't show a completed
solution without some work shown by the poser.

Thanks. Point taken.