Radicals

sistdm78

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Joined
Sep 10, 2010
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4
I am having trouble figuring out a math problem it is ³?729/343
This is what I have so far but I am unsure where to go from here if this is the correct path to take
729= 3, 243; 9, 81; 1, 729
343=1, 343; 7, 49
 
Is this what you mean?:

7293433\displaystyle \sqrt[3]{\frac{729}{343}}

If so, what is 93\displaystyle 9^{3} and 73\displaystyle 7^{3}?.
 
No, that was a typo. You know me. For heaven's sake, no 'text' speak. :oops:
 
sistdm78 said:
I am having trouble figuring out a math problem it is ³?729/343.

When you type out horizontally, put grouping symbols, such as parentheses, then make it look similar to (3729/343).\displaystyle \sqrt[3](729/343).

Otherwise, from the order of operations, what you have typed is equivalent to: 7293343\displaystyle \frac{\sqrt[3]{729}}{343},
but that is not what you wanted.

Another example:

2/3=23\displaystyle \sqrt 2/3 = \frac {\sqrt{2}}{3}

and (2/3)=  23.\displaystyle \sqrt(2/3) = \ \ \sqrt \frac{2}{3}.
 
lookagain said:
sistdm78 said:
I am having trouble figuring out a math problem it is ³?729/343.

When you type out horizontally, put grouping symbols, such as parentheses, then make it look similar to (3729/343).\displaystyle \sqrt[3](729/343).

Otherwise, from the order of operations, what you have typed is equivalent to: 7293343\displaystyle \frac{\sqrt[3]{729}}{343},
but that is not what you wanted.

Another example:

2/3=23\displaystyle \sqrt 2/3 = \frac {\sqrt{2}}{3}

and (2/3)=  23.\displaystyle \sqrt(2/3) = \ \ \sqrt \frac{2}{3}.

Watch for this one though:

2/3 = 23\displaystyle \sqrt {2/3} \ = \ \sqrt \frac{2}{3}
 
7293433 = (729343)1/3 = (9373)1/3 = (93)1/3(73)1/3 = 97.\displaystyle \sqrt[3]{\frac{729}{343}} \ = \ \bigg(\frac{729}{343}\bigg)^{1/3} \ = \ \bigg(\frac{9^3}{7^3}\bigg)^{1/3} \ = \ \frac{(9^3)^{1/3}}{(7^3)^{1/3}} \ = \ \frac{9}{7}.
 
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