rate of change -exponential

rajendrarama

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Dec 4, 2013
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The revenue equation for a product is given by R = 59x e^(-0.000015x) , x>=0. Find the value of 'x' for which its marginal revenue is zero. Hence, determine the maximum revenue.

I could do

dR/dx = 59[{x(e^(-0.000015x) (-0.000015)} + e^(-0.000015x)]

a) find the value of 'x' for which its marginal revenue is zero, does it mean to solve for 'x' when R=0 in the equation R = 59x e^(-0.000015x)
b) Maximum Revenue, does this mean to solve for 'x' when dR/dx=0 ?

Could you please help on this?
 
a) find the value of 'x' for which its marginal revenue is zero, does it mean to solve for 'x' when R=0 in the equation R = 59x e^(-0.000015x)
Hint: What is the definition of "marginal revenue", in terms of the revenue function? ;)
 
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