rajendrarama
New member
- Joined
- Dec 4, 2013
- Messages
- 6
The revenue equation for a product is given by R = 59x e^(-0.000015x) , x>=0. Find the value of 'x' for which its marginal revenue is zero. Hence, determine the maximum revenue.
I could do
dR/dx = 59[{x(e^(-0.000015x) (-0.000015)} + e^(-0.000015x)]
a) find the value of 'x' for which its marginal revenue is zero, does it mean to solve for 'x' when R=0 in the equation R = 59x e^(-0.000015x)
b) Maximum Revenue, does this mean to solve for 'x' when dR/dx=0 ?
Could you please help on this?
I could do
dR/dx = 59[{x(e^(-0.000015x) (-0.000015)} + e^(-0.000015x)]
a) find the value of 'x' for which its marginal revenue is zero, does it mean to solve for 'x' when R=0 in the equation R = 59x e^(-0.000015x)
b) Maximum Revenue, does this mean to solve for 'x' when dR/dx=0 ?
Could you please help on this?