B bobisaka Junior Member Joined Dec 25, 2019 Messages 115 Aug 7, 2021 #1 in my understanding the denominator would become : Than the fourth root would be: 2x In the textbook example, in the second step in screenshot, how did they simplify without the radical: And than how did they get x as their final answer? Last edited: Aug 7, 2021
in my understanding the denominator would become : Than the fourth root would be: 2x In the textbook example, in the second step in screenshot, how did they simplify without the radical: And than how did they get x as their final answer?
J JeffM Elite Member Joined Sep 14, 2012 Messages 7,874 Aug 7, 2021 #2 You are correct [math]\sqrt[4]{2^4x^4} = 2x.[/math] Whoever “they” may be, their second line is wrong. Their third line, however, is correct. The factors of 2 in numerator and denominator cancel.
You are correct [math]\sqrt[4]{2^4x^4} = 2x.[/math] Whoever “they” may be, their second line is wrong. Their third line, however, is correct. The factors of 2 in numerator and denominator cancel.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Aug 7, 2021 #3 JeffM said: [math]\sqrt[4]{2^4x^4} = 2x.[/math] Click to expand... Actually it should be [imath]\sqrt[4]{2^4x^4} = 2\large{|x|}.[/imath]
JeffM said: [math]\sqrt[4]{2^4x^4} = 2x.[/math] Click to expand... Actually it should be [imath]\sqrt[4]{2^4x^4} = 2\large{|x|}.[/imath]
Steven G Elite Member Joined Dec 30, 2014 Messages 14,603 Aug 7, 2021 #4 I 2nd pka's result. The simplification should be 2|x|.