Recurrence Relation..Can anyone solve it plz?

[anirban]

A(n) = A(n-1) + B(n-1) + C(n-1)
B(n) = 3^(n-1) - C(n-1)
C(n) = 3^(n-1) - B(n-1)
A(1) = B(1) = C(1) = 1

Best if solved using generating function!

 

[fasteddie65]

I put the equations into my TI-84 calculator, using SEQ mode.
Here's a glimpse of what turned up"

n A(n) B(n) C(n)
1 1 1 1
2 3 2 2
3 7 7 7
4 21 20 20
5 61 61 61
6 183 182 182


.....

 

[anirban]

Ya later i solved it using Generating functions
Anyway thanks for helping!