This wasn't isn't too hard to figure out
∫15f(x)dx
interval:
[1,5]
n=2 - because it wants two sub-intervals
a=1
b=5
We use
Δ(x)= width
=nb−a=25−1=2
Now we know that each interval is
2. So now we need to find the midpoint of each interval using the formula:
M1=2L1+R2
We know what
L1 and
R2 are for each interval, by looking at a graph we will draw.
Now you would have
(x1),(x2) which represent each midpoint.
Finally, to find the area under the curve:
Δ(x)[f(x1)+f(x2)]= area
Look right