Right Triangle Trigonometry

[cole92]

Directions: Use the given function values and the trigonometric identities to find the indicated trigonometric functions.

1. sin 60 degree = (sq. rt. 3 )/ 2 and cos 60 degree = 1/2
(a) find tan 60 degree
(b) find sin 30 degree
(c) find cos 30 degree
(d) find cot 60 degree

I was able to complete number one but if anyone can work it out I would like to check my answers

2. sin 30 degree = 1/2 and tan 30 degree = (sq. rt. 3)/ 3
(a) find csc 30 degree
(b) find cot 60 degree
(c) find cos 30 degree
(d) find cot 30 degree

Thanks for any help

 

[Deleted member 4993]

Directions: Use the given function values and the trigonometric identities to find the indicated trigonometric functions.

1. sin 60 degree = (sq. rt. 3 )/ 2 and cos 60 degree = 1/2
(a) find tan 60 degree
(b) find sin 30 degree
(c) find cos 30 degree
(d) find cot 60 degree

I was able to complete number one but if anyone can work it out I would like to check my answers

Where are your answers for us to check?
2. sin 30 degree = 1/2 and tan 30 degree = (sq. rt. 3)/ 3
(a) find csc 30 degree
(b) find cot 60 degree
(c) find cos 30 degree
(d) find cot 30 degree

Thanks for any help

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.

 

[Aladdin]

tan60=sin60/cos60=(sq. rt. 3 )/ 2/1/2
=2(sq. rt. 3 )/ 2
Since 30+60=90(complemantary angles )so:sin(30)=cos(60)and cos(30)=sin(60)
Cot60=cos60/sin60
=1/2/(sq. rt. 3 )/ 2
=2/2(sq. rt. 3 )


csc(30) = 1 / sin30
=1/1/2
=2
Now, I think its not necessirly to follow the alphabet order :
sin^2(30)+cos^2(30)=1
cos^2(30)= - sin^2(30)+1
cos(30)= - 1/4+1
cos(30)=3/4
(You can use different ways)
cot60=cos60/sin60