Rocket Integration doubt

[motocross179]

Hello thank you for providing this service you are godblessed for doing it for free. I just had a doubt on why in [the following] picture when he solves the integral he puts -1/m in front of the logarithm. Because the m is treated as a constant wouldn't it be appropriate to just leave it out of the parenthesis and solve the integral as a normal 1/x integral? Thanks