Rolle's Theorem + Mean Value Theorem

Taliaferro

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Hello friends! I need your insight on this problem.

i. Use Rolle's theorem to prove that \(\displaystyle f(x)\, =\, 3x^5\, +\, 10x^3\, +\, 15x\, +\, 2\) has at most one real root.
HINT: If \(\displaystyle f\) has two roots (say \(\displaystyle a\) and \(\displaystyle b\)) then \(\displaystyle f(a)\, =\, f(b)\, =\, 0.\) What does Rolle's theorem say in this situation?

ii. Let \(\displaystyle f\) be continuous on \(\displaystyle [a,\, b]\) and differentiable on \(\displaystyle (a,\, b).\) Show that there exists \(\displaystyle c\, \in\, (a,\, b)\) such that the tangent at \(\displaystyle \left(c,\, f(c)\right)\) is parallel to the secant through \(\displaystyle \left(a,\, f(a)\right)\) and \(\displaystyle \left(b,\, f(b)\right).\) In other words, show that:

. . . . .\(\displaystyle f'(c)\, =\, \dfrac{f(b)\, -\, f(a)}{b\, -\, a}\). . . . .\(\displaystyle (1)\)

Equation \(\displaystyle (1)\) is known as the Mean Value Theorem formula.
HINT: Apply Rolle's theorem on \(\displaystyle [a,\, b]\) to the function


. . . . .\(\displaystyle G(x)\, =\, \left(f(b)\, -\, f(a)\right)(x\, -\, a)\, +\, \left(f(b)\, -\, f(x)\right)(b\, -\, a)\)

Keep in mind that \(\displaystyle a,\, f(a),\, b, \) and \(\displaystyle f(b)\) are constants.


The first part I believe I understand. Rolle's theorem states that a continuous/differentiable function that has equal values at two distinct points must have a point between them where the first derivative is zero. Therefore if the polynomial has 2 or more roots there would be f(a) = 0 = f(b) and there would be a c in (a , b) where f'(c)=0

So the derivative is

. . . . .\(\displaystyle \displaystyle{f'(x)\, =\, 15x^4\, +\, 30x^2\, +\, 15}\)

Since f'(x) is positive, or greater than 0 for all x then there is no f'(c)=0 and there must be at most one real root, am I correct in my justification?

My real question comes from how to tackle the second part of the problem (it was especially the HINT that confused me). I get what the problem is asking me graphically, but for some reason I'm having trouble doing the actual math.

Very crude drawing of how I picture in my mind what the second part of the problem is asking me (see below)

001.jpg

I appreciate any help you can offer! :rolleyes:
 
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Update: If Im doing this right Im trying to show the slope of the secant line is equal to f'(c).

I arbitrarily chose [0, 1] as the interval. And if I've got it right this may just come down to an algebra question for me. Im not sure how to get 28 to equal the derivative.

001.jpg
 
Yes, because \(\displaystyle f'(x)= 15x^4+ 30x^2+ 15\) is always greater than 0, there can be at most one value of x for which f(x)= 0.

For the second part of the problem you are specifically told to look at \(\displaystyle G(x)= (f(b)- f(a))(x- a)+ (f(b)- f(x))(b- a)\).

What is G(a)? What is G(b)? How does Rolle's theorem apply to that?

No, you cannot simply take a= 0 and b= 1.
 
What is G(a)? What is G(b)? How does Rolle's theorem apply to that?
I dont know the answer to any of these simple questions.:oops:

is G(a)= 15a4 + 30a2+ 15

or is it G(a)= 3a5 + 10x3+ 15x + 2?

Im not sure what plugs in where. I think I get tripped up with what exactly G(x) or F(x) is asking me. I mean its an integral, right? I dont get how to set it up though:oops:
 
What is G(a)? What is G(b)? How does Rolle's theorem apply to that?
I dont know the answer to any of these simple questions.
If you don't know how to plug "a" in for "x" in the formula they gave you for G(x), then I fear that you may need much more help than we can here provide. It would appear that you may need to go back and learn the algebra you've missed. (They would have covered "function notation" and the evaluation of functions in any pre-calculus algebra course.)

I get tripped up with what exactly G(x) or F(x) is asking me. I mean its an integral, right?
Please point out where the original exercise has any "F(x)", where G(x) is defined as anything other than a function of f(x) and two named constants, and where there is any integral mentioned or suggested anywhere. :shock:
 
If you don't know how to plug "a" in for "x" in the formula they gave you for G(x), then

I fear that you may need much more help than we can here provide. It would appear that you may need to go back and learn the algebra you've missed. (They would have covered "function notation" and the evaluation of functions in any pre-calculus algebra course.)

Tell me about it! lol. You guys have been so helpful thus far though. I figure ill just fake it till I make it :cool:

plug "a" in for "x" in the formula they gave you for G(x)

I dont see what the value is for a. Unless that literally means everywhere after "G(x)" that I see an 'x' I replace it with an 'a'. It that it?
 
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