T tamiatha Junior Member Joined Apr 26, 2009 Messages 109 Jun 14, 2009 #1 use the value of the discriminant to determine the number and type of roots for the equation: 2X^2-7X+9=0 number of roots=2 type of root=real are the roots real or imaginary
use the value of the discriminant to determine the number and type of roots for the equation: 2X^2-7X+9=0 number of roots=2 type of root=real are the roots real or imaginary
L Loren Senior Member Joined Aug 28, 2007 Messages 1,298 Jun 14, 2009 #2 Re: roots (e7q13) 2X^2=7X+9=0 <<<< Typo???
T tamiatha Junior Member Joined Apr 26, 2009 Messages 109 Jun 14, 2009 #3 Re: roots (e7q13) yes typo sorry 2x^2-7x+9=0
L Loren Senior Member Joined Aug 28, 2007 Messages 1,298 Jun 14, 2009 #4 Re: roots (e7q13) 2x^2-7x+9=0 a=2, b=-7, c=9 The discriminant is \(\displaystyle \pm\sqrt{b^2-4ac}\) What kinds of numbers do you get when you plug in the givens and evaluate?
Re: roots (e7q13) 2x^2-7x+9=0 a=2, b=-7, c=9 The discriminant is \(\displaystyle \pm\sqrt{b^2-4ac}\) What kinds of numbers do you get when you plug in the givens and evaluate?