sequence evaluation - limit with e

[mooltipas13]

Hi,
I am stuck on this sequence -
(2e^(n+1))/(e^n)
Tried to evaluate:
Limit as n approaches infinity (2e^(n+1))/(e^n)=2e^(infinity)/e^(infinity)=2 - but I know the answer to this is 2e... where am I going wrong?

Thanks!
Mooltipas

 

[tkhunny]

\(\displaystyle e^{n+1} = e^{n}\cdot e\)

\(\displaystyle \frac{e^{n}}{e^{n}} = 1\)

 

[mooltipas13]

Thanks! Duh!

 

[tkhunny]

:wink: No worries. It happens.

I once had an important paper returned in my first linear algebra class. The hand-written note from the professor stated, "I should fail you for the whole semester for this." I learned to be more careful and keep my eyes open a little wider.