series convergence: sum [n=1, infty] [ 3/(5^n) + 2/n ]

[summergrl]

Determine whether the series is convergent or divergent. If it is convergent, find its sum.

Sum from n=1 to infinity of ( 3/(5^n) + 2/n)

 

[galactus]

Look at the 2/n. That is definitely divergent because 1/n is divergent.