Set up triple integrals in Cylindrical and Spherical coordinates

bscouth

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Nov 6, 2015
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I have no idea to set this integral, please help:

1, the first octane bounded above by z=x and x2+y2 = 4 for triple integral in Cylindrical coordinate: This is what i have
(1st integral) 0 to pi/2 (2nd integral) 0 to 1 (3rd integral) rcos(theta) to (1-r2) then r dz dr dtheta

2, Triple integral in Spherical coordinates z= sqrt(25-x2-y2) and x2+y2=4 for this one i have no idea?

this 2 question i had spent 2 days with it but still no light, please help!
 
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