Nvm sry i figured out the answer
G grapz Junior Member Joined Jan 13, 2007 Messages 80 Sep 17, 2007 #1 Nvm sry i figured out the answer
J jwpaine Full Member Joined Mar 10, 2007 Messages 723 Sep 17, 2007 #2 grapz said: [ x + (1/x) + 1] / [ x + (1/x) + 2] I tried to just multiply the top by x, but it seems i get the wrong answer Click to expand... \(\displaystyle \L \frac{x + (1/x) + 1}{x + (1/x) + 2}\) I would combine all terms in the numerator and denominator into single fractions, and then simplify: = \(\displaystyle \L \frac{\frac{x}{1} + \frac{1}{x} + \frac{1}{1}}{\frac{x}{1} + \frac{1}{x} + \frac{2}{1}}\) = \(\displaystyle \L \frac{\frac{x^2+1}{x} + \frac{1}{1}}{\frac{x^2 + 1}{x} + \frac{2}{1}}\) = \(\displaystyle \L \frac{\frac{x^2+1 + x}{x}}{\frac{x^2 + 1 + 2x}{x}}\) = \(\displaystyle \L \frac{x^2+1 + x}{x}\cdot\frac{x}{x^2 + 1 + 2x}\) = \(\displaystyle \L \frac{x^2+1 + x}{x^2 + 1 + 2x}\)
grapz said: [ x + (1/x) + 1] / [ x + (1/x) + 2] I tried to just multiply the top by x, but it seems i get the wrong answer Click to expand... \(\displaystyle \L \frac{x + (1/x) + 1}{x + (1/x) + 2}\) I would combine all terms in the numerator and denominator into single fractions, and then simplify: = \(\displaystyle \L \frac{\frac{x}{1} + \frac{1}{x} + \frac{1}{1}}{\frac{x}{1} + \frac{1}{x} + \frac{2}{1}}\) = \(\displaystyle \L \frac{\frac{x^2+1}{x} + \frac{1}{1}}{\frac{x^2 + 1}{x} + \frac{2}{1}}\) = \(\displaystyle \L \frac{\frac{x^2+1 + x}{x}}{\frac{x^2 + 1 + 2x}{x}}\) = \(\displaystyle \L \frac{x^2+1 + x}{x}\cdot\frac{x}{x^2 + 1 + 2x}\) = \(\displaystyle \L \frac{x^2+1 + x}{x^2 + 1 + 2x}\)
