M Maria13 New member Joined Oct 4, 2006 Messages 1 Oct 4, 2006 #1 Hi you guys! Trying to remember how this stuff works, check it out: [(6x - 18) / (3x^2 + 2x - 8)] × [(12x - 16) / (4x - 12)] I would appreciate your help!
Hi you guys! Trying to remember how this stuff works, check it out: [(6x - 18) / (3x^2 + 2x - 8)] × [(12x - 16) / (4x - 12)] I would appreciate your help!
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Oct 4, 2006 #2 \(\displaystyle \L\\\frac{6x-18}{3x^{2}+2x-8}\cdot\frac{12x-16}{4x-12}\) Factor the respective numerators and denominators and cancel: \(\displaystyle \L\\\frac{6(x-3)}{(3x-4)(x+2)}\cdot\frac{4(3x-4)}{4(x-3)}\) I'll leave you finish. Okey-doke?.
\(\displaystyle \L\\\frac{6x-18}{3x^{2}+2x-8}\cdot\frac{12x-16}{4x-12}\) Factor the respective numerators and denominators and cancel: \(\displaystyle \L\\\frac{6(x-3)}{(3x-4)(x+2)}\cdot\frac{4(3x-4)}{4(x-3)}\) I'll leave you finish. Okey-doke?.
