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Simplify(25x^2y^4) over (-5x^2y^-2) all raised by 2nd power
- Thread starter Kush08
- Start date
Right now, I have:
50x[sup:y0csyjmw]4[/sup:y0csyjmw]y[sup:y0csyjmw]8[/sup:y0csyjmw] over -10x[sup:y0csyjmw]12[/sup:y0csyjmw]y[sup:y0csyjmw]-4[/sup:y0csyjmw]
I'm wondering whether I should have done -5 * -5 to get 25 on bottom instead of the -10...
please help :/
50x[sup:y0csyjmw]4[/sup:y0csyjmw]y[sup:y0csyjmw]8[/sup:y0csyjmw] over -10x[sup:y0csyjmw]12[/sup:y0csyjmw]y[sup:y0csyjmw]-4[/sup:y0csyjmw]
I'm wondering whether I should have done -5 * -5 to get 25 on bottom instead of the -10...
please help :/
(25x[sup:3w52ywki]2[/sup:3w52ywki]y[sup:3w52ywki]4[/sup:3w52ywki]) over (-5x[sup:3w52ywki]2[/sup:3w52ywki]y[sup:3w52ywki]-2[/sup:3w52ywki])
\(\displaystyle \frac{25x^2y^4}{-5x^2y^{-2}}=\left(\frac{25}{-5}\right)\left(\frac{x^2}{x^2}\right)\left(\frac{y^4}{y^{-2}}\right)\)
Now, work on that.
\(\displaystyle \frac{25x^2y^4}{-5x^2y^{-2}}=\left(\frac{25}{-5}\right)\left(\frac{x^2}{x^2}\right)\left(\frac{y^4}{y^{-2}}\right)\)
Now, work on that.