simplify [4k^4+6k^3+3k-1] /[2k^2+1]

[jshaziza]

I need some help on this equation. I have to divide 4k to the 4 +6k to the 3 +3k -1
by 2k to the 2 + 1

thx in advance for any help

 

[arthur ohlsten]

[4k^4+6k^3+3k-1] /[2k^2+1]

the problem I have is that everything is moved to the left when I submit this. You set it up as a long division problem and divide, and you will understand the listing below

divide as you did in 5th grade
2k^2+3k-1
-------------------------------------
2k^2+1 l 4k^4+6k^3+0k^2+3k-1
4k^4 +2k^2
------------------------
6k^3-2k^2
6k^3 +3k
------------------------
-2k^2 -1
-2k^2 -1
-------------------
0
Arthur

 

[arthur ohlsten]

[4k^4+6k^3+3k-1] /[2k^2+1]

when you divide as in 6th grade the first term will be2k^2. when you multiply this by the divisor you get
4k^4+2k^2
when you subtract this and bring down the next term you have
6k^3-2k^2+3k-1
when you divide 2k^2+1 into this you get +3k
when you multiply this by the divisor you get
6k^3+3k
when you subtract this you get
-2k^2-1
when you divide this by the divisor you get -1
when you multiply this by the divisor you get -2k^2-1
when you subtract this you get a remainder of 0

across the top you have
2k^2+3k-1 answer
Arthur