Simplify exponents + variables

Please show us what you can do, so we can tell where you are stuck or wrong, and help where you need help.

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Specifically, there are many orders in which you might do things, and if I told you where I'd start, it might not agree with your own inclinations (or even with what you've been taught), and you might wrongly think you were wrong.
 
Dr.Peterson said:
Please show us what you can do, so we can tell where you are stuck or wrong, and help where you need help.

See our guidelines:

Posting Guidelines (Summary)

Welcome to our tutoring boards! :) This page summarizes the main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We don't do your homework. We prefer to...
www.freemathhelp.com

Specifically, there are many orders in which you might do things, and if I told you where I'd start, it might not agree with your own inclinations (or even with what you've been taught), and you might wrongly think you were wrong.
Click to expand...

This is what I've been able to do so far. I'm not sure if I've done it correctly or if its in the simplest form.

((x-2y3+x3y6)(1/2)))/x-2y
= ((y3/x2)+x3y6)(1/2))/x-2
= (((y3+x5y6)/x2)(1/2))/(1/x2))
= x(y3+x5y6)(1/2)
 
Last edited:
hfkajfuheuifheiufh said:
This is what I've been able to do so far. I'm not sure if I've done it correctly or if its in the simplest form.

((x-2y3+x3y6)(1/2)))/x-2y
= ((y3/x2)+x3y6)(1/2))/x-2
= (((y3+x5y6)/x2)(1/2))/(1/x2))
= x(y3+x5y6)(1/2)
Click to expand...
On the whole, that looks good. (I corrected a few typos above). Here are the only errors I see:
  1. You seem to have lost the y in the denominator -- assuming you meant ((x-2y3+x3y6)(1/2))/(x-2y)
  2. I thought I saw another error, but you'd just skipped a step
  3. At the end, you could factor out a y2 from the radicand, and pull it outside ... and that would cancel with the y you dropped at the start.
 
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