P pjlloyd New member Joined Oct 25, 2011 Messages 2 Oct 25, 2011 #1 I can't figure this out! (e^-1+f^-1)/(e+f) Help anyone D:
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Oct 25, 2011 #2 Hello, pjlloyd! Exactly where are you stuck? \(\displaystyle \text{Simplify: }\:\dfrac{e^{-1} + f^{-1}}{e+f}\) Click to expand... We have: .\(\displaystyle \dfrac{\frac{1}{e} + \frac{1}{f}}{e+f}\) Multiply by \(\displaystyle \frac{ef}{ef}:\;\;\dfrac{ef\left(\frac{1}{e} + \frac{1}{f}\right)}{ef(e+f)} \;=\; \dfrac{f+e}{ef(e+f)} \;=\;\dfrac{1}{ef}\)
Hello, pjlloyd! Exactly where are you stuck? \(\displaystyle \text{Simplify: }\:\dfrac{e^{-1} + f^{-1}}{e+f}\) Click to expand... We have: .\(\displaystyle \dfrac{\frac{1}{e} + \frac{1}{f}}{e+f}\) Multiply by \(\displaystyle \frac{ef}{ef}:\;\;\dfrac{ef\left(\frac{1}{e} + \frac{1}{f}\right)}{ef(e+f)} \;=\; \dfrac{f+e}{ef(e+f)} \;=\;\dfrac{1}{ef}\)
P pjlloyd New member Joined Oct 25, 2011 Messages 2 Oct 25, 2011 #3 I don't understand why you multiplied by ef? When I was doing it, I was multiplying by the conjugate? But thanks a bunch!
I don't understand why you multiplied by ef? When I was doing it, I was multiplying by the conjugate? But thanks a bunch!
