W wilc0919 New member Joined Oct 13, 2006 Messages 37 Nov 27, 2006 #1 Simplify the following usinf properties of logs and exponents: ln ( x^2 e ^ -ln to the sq.root of x) I get ln(x^2 e^x1/ln)
Simplify the following usinf properties of logs and exponents: ln ( x^2 e ^ -ln to the sq.root of x) I get ln(x^2 e^x1/ln)
A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 847 Nov 27, 2006 #2 y=ln[x^2 e^-lnx^1/2] y=ln[x^2/e^lnx^1/2] y=lnx^2 -ln e^lnx^1/2 but e^lnz=z or y=lnx^2-lnx^1/2 y=ln[x^2/x^1/2] y=ln x^3/2 y=3/2 ln x answer Arthur
y=ln[x^2 e^-lnx^1/2] y=ln[x^2/e^lnx^1/2] y=lnx^2 -ln e^lnx^1/2 but e^lnz=z or y=lnx^2-lnx^1/2 y=ln[x^2/x^1/2] y=ln x^3/2 y=3/2 ln x answer Arthur
