Simplify

greatwhiteshark

Full Member
Joined
May 8, 2005
Messages
279
sqrt = square root

(sqrt2x - 3/sqrt2x^4 + 3x^3) sqrtx/sqrt4x^2 - 9

ALL numbers in the numerator and denominator are within radicals.
 
What do you have against ()s? The written comments keep it from being confused but it should look like...
sqrt(2x - 3)/sqrt(2x^4 + 3x^3)* sqrt(x)/sqrt(4x^2 - 9) =
sqrt(2x - 3)/(x*sqrt(x)*sqrt(2x + 3) * sqrt(x)/(sqrt(2x - 3)*sqrt(2x + 3))
Can you finish it?
 
Yes...

I can take it fro here. I never ask for the answer. I just want the equation or steps to help me solve it alone.
 
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