Simplifying Expressions

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Aug 18, 2011
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I'm currently doing an Algebra I review for the Algebra II/Trig class I'll be going into this year, and I honestly have NO IDEA what I'm doing (Luckily I have about a month to work things out).

Anyhow, I'm fine with some things, but right now I'm in a "sketchy-to-WHAT IS THIS?" area.

I need to simplify expressions like this: (2y)(4xy^3) and after multiplying 2y with 4x and y^3 I ended up with 8x2y^5. Is that correct? There are quite a few here, and I just want to make sure I'm on the right track.

Unfortunately there are a few that I don't even know where to start with, like: (3/4c^2f)(4/3cd). I get the gut reaction to do something like FOIL for that, but there's no way. I suppose multiplying 3/4(4/3cd) and then c^2(4/3cd) and then f(4/3cd) and simplifying?

Just some reassurance that I'm doing things correctly/explanation would be appreciated. Oh, and what exactly are expressions like those called? I couldn't look up explanations on my own because I have no idea what to call them.

Thank you in advance!
 
No, not quite. 2y(4xy3) = 8xy4. Was y5 a typo? If not, why would you ever think that 2 * 23 = 2 * 8 = 16 = 32 = 25?
Oh man, I'm overthinking it, I guess. I think I did something along the lines of: 2y * 4x=8xy and 2y * y3= 2y4; and then 8xy * 2y4. I got an extra 2 and an extra y and lost the 2 somewhere.


Ahh. Remember that m / n is the same as
11_0c3c664dbb013e81bb215a46dbe7e505.png
. Also remember how you multiply fractions:
(m / n) * (p/q) =
41_02b8260cfea9e7f90d34fa618491a400.png
=
(mp) / (nq). Numerators times numerators and denominators times denominators. Now try working your problem out.

(3/4C2f)(4/3cd) = (12/12C3df) or just c3df ?

If that's right I'm fairly positive I'm just overthinking a lot of this and trying to do something like FOIL when I should just multiply like terms?

Thank you!
 
...Oy, I replied to you yesterday, but my post seems to have never gotten through. Lucky, I suppose. It was a bit ramble-y.

I think I see what I'm doing wrong. I'm super over-complicating things and trying to do something like FOIL when I should just be multiplying like terms?

So with 2y(4xy3) I was doing this: 2y * 4x = 2y4x and 2y * y3 = 2y4 and then multiplying 2y4x * 2y4 (and losing that extra 2 somewhere) when I should have just multiplied 2 * 4 and y * y3?

Using that method, (3/4c2f)(4/3cd) = c3df?
 
Oh, wow, yes, thank you so much! I don't believe I was ever taught that (or well enough, at least).

And, yes, that's what I meant. Sorry if my notation is a bit off/confusing.

Thank you! I'm fairly sure I'll be back with more questions eventually, so I'll be seeing you around, I suppose, haha.
 
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