H HATLEY1997 Junior Member Joined Oct 24, 2023 Messages 59 Oct 24, 2023 #1 Can this be simplified any further?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,579 Oct 24, 2023 #2 HATLEY1997 said: Simplify using "flip" method: [imath]\qquad \left(\dfrac{p}{q}\right)\, \div \, \left(\dfrac{6p^3 - 2qp^2}{q^4 - 3q^3 p}\right)[/imath] My answer: [imath]\qquad \dfrac{p(q^4 - 3q^3 p)}{q(6p^3 - 2qp^2)}[/imath] Can this be simplified any further? Click to expand... I'm not seeing that this has been simplified yet at all. To get started on that, try factoring the parentheticals. There is one cancellation.
HATLEY1997 said: Simplify using "flip" method: [imath]\qquad \left(\dfrac{p}{q}\right)\, \div \, \left(\dfrac{6p^3 - 2qp^2}{q^4 - 3q^3 p}\right)[/imath] My answer: [imath]\qquad \dfrac{p(q^4 - 3q^3 p)}{q(6p^3 - 2qp^2)}[/imath] Can this be simplified any further? Click to expand... I'm not seeing that this has been simplified yet at all. To get started on that, try factoring the parentheticals. There is one cancellation.