simplifying fractions 2 answers??

freshmaker

New member
Joined
Nov 14, 2016
Messages
6
Hi I've been given this fraction to simplify :

1 + 1
--
x
--------
x

so I would simplify as

1 1 1 1 1 2
-- + -- x --- --> -- + --- --> --
x 1 x x x x

now, apparently I'm incorrect as the correct answer given is

1 x 1 1+x 1 1+x
-- + -- x -- ----> ---- x -- -----> ----
x x x x x x^2

can anyone explain why I am wrong.
 
Hi I've been given this fraction to simplify :

1 + 1
--
x
--------
x

Well, as you can see, the forum didn't preserve any of the whitespace-based formatting you used here. I'll guess that your original problem was (1 + 1/x) / x. If that's not right, please reply with any necessary corrections.

so I would simplify as

1 1 1 1 1 2
-- + -- x --- --> -- + --- --> --
x 1 x x x x

now, apparently I'm incorrect as the correct answer given is

1 x 1 1+x 1 1+x
-- + -- x -- ----> ---- x -- -----> ----
x x x x x x^2

can anyone explain why I am wrong.

Sorry, but I'm not even remotely sure what any of your workings or the given solution are meant to signify, as they both got turned into nonsense. When you reply back, please type out both your work and the solution in the manner shown above, using the / symbol to indicate division. Also note that parentheses will prove very important. 1 + x / x is not the same as (1 + x) / x. Be sure you understand why.
 
Hi I've been given this fraction to simplify :

1 + 1
--
x
--------
x
To learn how to format math as text, please try here. Pay particular attention to grouping symbols. For instance, if grouped as follows:

. . . . .[(1/x) + 1] / x

...the expression typesets as:

. . . . .\(\displaystyle \dfrac{\left(\dfrac{1}{x}\, +\, 1\right)}{x}\)

However, if grouped as follows:

. . . . .(1 + 1)/(x/x)

...the expression typesets as:

. . . . .\(\displaystyle \dfrac{1\, +\, 1}{\left(\dfrac{x}{x}\right)}\)

I suspect your meaning is closer to the former than to the latter...? ;)
 
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