simplyfying ((1/2)-(1/x))/(x-2)

[kpx001]

((1/2)-(1/x))/(x-2)

x/(2x)-(2/2x)/(x-2)
then combine to get

(x-2)/2x/(x-2)
then i do the reciprocol

(x-2)/2x times 1/(x-2)

the x-2 can be canceled to get one, and the final answer is
1/2x ??

this is how far i got till i get confused
thanks

 

[tkhunny]

Except for some notation problems, you're done. You should not get confused after you are done. You got it!! Good work.

Note:

x/(2x)-(2/2x)/(x-2)

This doesn't mean what you want. More parentheses.

[x/(2x)-(2/2x)]/(x-2)

 

[Denis]

x/(2x)-(2/2x)/(x-2)
This doesn't mean what you want. More parentheses.
[x/(2x)-(2/2x)]/(x-2)

TK, shuddn't dat b [x / (2x) - 2 / (2x)] / (x - 2) :?:

 

[tkhunny]

I'm having a little trouble seeing the difference. No sin in extra, but correct, parentheses.

 

[Denis]

What I'm getting at is 2/2x is not same as 2/(2x)

 

[tkhunny]

Right. Missed it - even after staring at it for a while.

I guess I group a single value and its associated variable in my head.