J Jason76 Senior Member Joined Oct 19, 2012 Messages 1,180 Oct 12, 2013 #1 \(\displaystyle y = \sin(\tan 5x)\) \(\displaystyle \cos(u) du\) \(\displaystyle \cos(u)[(v) dv]\) \(\displaystyle \cos(u)[(v) 5]\) \(\displaystyle \cos(u)[(\sec^{2} 5x) 5] \) \(\displaystyle \cos(\tan 5x)[5 \sec^{2} 5x] \) Last edited: Oct 12, 2013
\(\displaystyle y = \sin(\tan 5x)\) \(\displaystyle \cos(u) du\) \(\displaystyle \cos(u)[(v) dv]\) \(\displaystyle \cos(u)[(v) 5]\) \(\displaystyle \cos(u)[(\sec^{2} 5x) 5] \) \(\displaystyle \cos(\tan 5x)[5 \sec^{2} 5x] \)
F fcabanski Junior Member Joined Aug 17, 2013 Messages 77 Oct 12, 2013 #2 Your answer is correct. You can verify these on wolframalpha.com.
