Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the line y=4.
y=x
y=3
x=0
so, here's what i've done. I know the answer i got is wrong, but i can't see where i slipped up. However, this is new stuff to me so im not too comfortable with it yet.
V=π∫([R(x)]2−[r(x)]2)dx
outer radius R(x) i think should be 3-x
inner radius r(x) seems to be a constant 1
so therefore, it seems to me that the following would give me the correct answer.
V=π∫([3−x]2−[1]2)dx (from 0 to 3)
(I dont know the tex coding very well so i dont know how to make it display a definite integral with bounds.)
this gives the answer 6π but my text says it's supposed to be 18π
so where did i mess up?
thanks.
y=x
y=3
x=0
so, here's what i've done. I know the answer i got is wrong, but i can't see where i slipped up. However, this is new stuff to me so im not too comfortable with it yet.
V=π∫([R(x)]2−[r(x)]2)dx
outer radius R(x) i think should be 3-x
inner radius r(x) seems to be a constant 1
so therefore, it seems to me that the following would give me the correct answer.
V=π∫([3−x]2−[1]2)dx (from 0 to 3)
(I dont know the tex coding very well so i dont know how to make it display a definite integral with bounds.)
this gives the answer 6π but my text says it's supposed to be 18π
so where did i mess up?
thanks.