solution needed for: Find the supremum of G={ x | x^2+1)^-1 > 1/2}

allos

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Apr 26, 2016
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Find the supremum of
[FONT=MathJax_Math-italic]G​
[FONT=MathJax_Main]=[/FONT][FONT=MathJax_Size3]{[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]|x2[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]1[/FONT][FONT=MathJax_Main])-1 [/FONT][FONT=MathJax_Main]> 1/2[/FONT][FONT=MathJax_Size3]}[/FONT]​
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Find the supremum of
[FONT=MathJax_Math-italic]G​
[FONT=MathJax_Main]=[/FONT][FONT=MathJax_Size3]{[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]|x2[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]1[/FONT][FONT=MathJax_Main])-1 [/FONT][FONT=MathJax_Main]> 1/2[/FONT][FONT=MathJax_Size3]}[/FONT]​
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What are your thoughts?

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Find the supremum of [FONT=MathJax_Math-italic]G[/FONT][FONT=MathJax_Main]=[/FONT][FONT=MathJax_Size3]{[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]|x2[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Main]1[/FONT][FONT=MathJax_Main])-1 [/FONT][FONT=MathJax_Main]> 1/2[/FONT][FONT=MathJax_Size3]}[/FONT]
Here is a huge hint.
 
Solution needed for:

Find the supremum of:

. . . . .\(\displaystyle G\, =\, \left\{\, x\, \vert\, (x^2\, +\, 1)^{-1}\, >\, \dfrac{1}{2}\, \right\}\)
Okay; you need a solution. What efforts have you made to obtain that solution (other than asking people online to do it for you)? ;)
 
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