solve 11 m – (1.5 m/s)t = (– 12 m) – (2.0 m/s)t + (0.85 m/s^

[synx]

solve 11 m – (1.5 m/s)t = (– 12 m) – (2.0 m/s)t + (0.85 m/s^

11 m – (1.5 m/s)t = (– 12 m) – (2.0 m/s)t + (0.85 m/s^2)t^2,

im suppose to somehow get t=5.5s and 4.9s from that.

 

[skeeter]

I'll bet that your inclusion of units for the coefficients has some folks confused (they might think them to be variables) ...

simple quadratic ...

11 - 1.5t = -12 - 2t + .85t²

collect like terms and set = 0 ...

0 = -23 - .5t + .85t²

now ... use the quadratic formula to solve for t

a = .85, b = -.5, c = -23

 

[Denis]

Re: solve 11 m – (1.5 m/s)t = (– 12 m) – (2.0 m/s)t + (0.85

11 m – (1.5 m/s)t = (– 12 m) – (2.0 m/s)t + (0.85 m/s^2)t^2,

im suppose to somehow get t=5.5s and 4.9s from that.

NO you're not!
You're suppose to get t = (10 +- sqrt(31380)) / 34)s,
which means t = (5.504...)s or t = (-4.916...)s

Reason there's no "m" in solution is they cancel out, leaving:
11 – 1.5t / s = –12 – 2t / s + .85t^2 / s^2

Rearrange, and multiply by s^2 to remove fractions,
and multiply by 100 to get rid of decimals:
17t^2 - 10st - 460s^2 = 0

Now solve for t, using quadratic formula.