T thepcnerd New member Joined Dec 4, 2006 Messages 14 Feb 18, 2007 #1 pls help with this problem... It's a solve for y in one equation problem. 2/3x-5/2y=5 I continue to get y=19x-25 but im sure its wrong, pls help me thanks
pls help with this problem... It's a solve for y in one equation problem. 2/3x-5/2y=5 I continue to get y=19x-25 but im sure its wrong, pls help me thanks
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Feb 18, 2007 #2 Onbe thing to do its multiply through by the LCM of the denomiantors in order to get rid of the fractions. The LCM of 2 and 3 is 6 \(\displaystyle \L\\6\cdot\frac{2}{3}x-6\cdot\frac{5}{2}y=6\cdot{5}\) \(\displaystyle \L\\4x-15y=30\) \(\displaystyle \L\\y=\frac{4}{15}x-2\)
Onbe thing to do its multiply through by the LCM of the denomiantors in order to get rid of the fractions. The LCM of 2 and 3 is 6 \(\displaystyle \L\\6\cdot\frac{2}{3}x-6\cdot\frac{5}{2}y=6\cdot{5}\) \(\displaystyle \L\\4x-15y=30\) \(\displaystyle \L\\y=\frac{4}{15}x-2\)
D Denis Senior Member Joined Feb 17, 2004 Messages 1,706 Feb 19, 2007 #3 Re: pls help with this problem thepcnerd said: 2/3x-5/2y=5 Click to expand... Really, you should write these this way: 2x / 3 - 5y / 2 = 5 Then it's much easier to see the denominators: 3 and 2 ; kapish?
Re: pls help with this problem thepcnerd said: 2/3x-5/2y=5 Click to expand... Really, you should write these this way: 2x / 3 - 5y / 2 = 5 Then it's much easier to see the denominators: 3 and 2 ; kapish?
