S sana125 New member Joined May 20, 2005 Messages 18 May 27, 2005 #1 Solve each Equation: x(x-2)=3 14/x^2-1 + 1/x-1 = 3/x+1 3x^2 + 2x +2 = 0 Please help me to solve these equation......Thanks!
Solve each Equation: x(x-2)=3 14/x^2-1 + 1/x-1 = 3/x+1 3x^2 + 2x +2 = 0 Please help me to solve these equation......Thanks!
E elchichita Guest May 27, 2005 #2 x(x-2)=3 is equivalent to x(x-2)-3=0, or x^2-2x-3=0, which means (simply by inspection) that x=-1 or x=3
x(x-2)=3 is equivalent to x(x-2)-3=0, or x^2-2x-3=0, which means (simply by inspection) that x=-1 or x=3
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 May 27, 2005 #3 sana125 said: 14/x^2-1 + 1/x-1 = 3/x+1 Click to expand... Think about the Domain: x != 1 and x!= -1 Find a common denominator: (x+1)*(x-1) Add the fractions and see what pops up. 3x^2 + 2x +2 = 0 Click to expand... Do we get to use Imaginary numbers? The Quadratic Formula will ALLWAYS tell you both solutions. b<sup>2</sup> - 4*a*c = 2<sup>2</sup> - 4*3*2 = 4 - 24 = -20 If we're stuck with Real numbers, we're done. Why?
sana125 said: 14/x^2-1 + 1/x-1 = 3/x+1 Click to expand... Think about the Domain: x != 1 and x!= -1 Find a common denominator: (x+1)*(x-1) Add the fractions and see what pops up. 3x^2 + 2x +2 = 0 Click to expand... Do we get to use Imaginary numbers? The Quadratic Formula will ALLWAYS tell you both solutions. b<sup>2</sup> - 4*a*c = 2<sup>2</sup> - 4*3*2 = 4 - 24 = -20 If we're stuck with Real numbers, we're done. Why?
S sana125 New member Joined May 20, 2005 Messages 18 May 28, 2005 #4 Tkhunny and elchichita, this is helps! Thanks for your input!