You are correct up to this pointSolve equation 3tan(2x+15)=4 for 0<x<180
My Workings:
tan(2x+15)=4/3
2x+15=arctan(4/3)
2x=arctan(4/3)-15
x=(arctan(4/3)-15)/2
x=-7.036
tan^1(-7.036)=-81.91
-81.91+180=98.089
Am I correct or did I mess up along the way:?:
Not trying to be rude but of course you are wrong. You are told that x is in between 0 and 180, yet you say that x=-7.036!Solve equation 3tan(2x+15)=4 for 0<x<180
My Workings:
tan(2x+15)=4/3
2x+15=arctan(4/3)
2x=arctan(4/3)-15
x=(arctan(4/3)-15)/2
x=-7.036
tan^1(-7.036)=-81.91
-81.91+180=98.089
Am I correct or did I mess up along the way:?:
Jomo,Not trying to be rude but of course you are wrong. You are told that x is in between 0 and 180, yet you say that x=-7.036!