S synapsis New member Joined Jan 19, 2006 Messages 28 Apr 13, 2006 #1 solve for x y=(x-9)/(3x-1) (3x-1)y=x-9 3xy-y=x-9 3xy-x=y-9 x(3y-1)=y-9 x=(y-9)/(3y-1) that's the answer i get... the book answer says x=(y+9)/(1-3y) is my math wrong or is that the same answer just written different?
solve for x y=(x-9)/(3x-1) (3x-1)y=x-9 3xy-y=x-9 3xy-x=y-9 x(3y-1)=y-9 x=(y-9)/(3y-1) that's the answer i get... the book answer says x=(y+9)/(1-3y) is my math wrong or is that the same answer just written different?
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Apr 13, 2006 #2 Your math is good. If the book had (-y+9) it would be "just written different." --------------- Gene
