C chanman3 New member Joined Dec 11, 2010 Messages 2 Dec 11, 2010 #1 For some reason I just can't get past this problem. 1/a = 1/b + 1/x lcd - abx (abx)1/a = (abx)1/b + (abx)1/x Then I get to bx = ax + ab Where do I go from there?
For some reason I just can't get past this problem. 1/a = 1/b + 1/x lcd - abx (abx)1/a = (abx)1/b + (abx)1/x Then I get to bx = ax + ab Where do I go from there?
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,116 Dec 11, 2010 #2 chanman3 said: For some reason I just can't get past this problem. 1/a = 1/b + 1/x lcd - abx (abx)1/a = (abx)1/b + (abx)1/x Then I get to bx = ax + ab Where do I go from there? Click to expand... Since you are trying to solve for x, get all terms containing x on one side of the equation, and everything else on the other side. If you subtract ax from both sides, you'll have this: bx - ax = ax + ab - ax bx - ax = ab Now....remove a common factor of x from both terms on the left side, and see if that helps.
chanman3 said: For some reason I just can't get past this problem. 1/a = 1/b + 1/x lcd - abx (abx)1/a = (abx)1/b + (abx)1/x Then I get to bx = ax + ab Where do I go from there? Click to expand... Since you are trying to solve for x, get all terms containing x on one side of the equation, and everything else on the other side. If you subtract ax from both sides, you'll have this: bx - ax = ax + ab - ax bx - ax = ab Now....remove a common factor of x from both terms on the left side, and see if that helps.
C chanman3 New member Joined Dec 11, 2010 Messages 2 Dec 12, 2010 #3 thank you very much. I guess I was looking at it so long I couldn't see it. Love this site!
