Solve Summation with Multiple Variables

diargos

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I have a little equation for which I need to solve for r. The problem I'm having is that I don't remember the techniques that can be used to do this, as the equation contains a summation. I spent some time on Google and in my old text books, but I haven't found anything yet. This is part of my equation:

The "(i=0 E y)" part is the Sigma notation.

F = (i=0 E y) Ci(1 + r)(t-i)


I want to solve for r, with F, Ci, t, and y all on the other side of the equation. Can anyone help me with where I should begin with this? What the steps would look like, or what keywords I can use in Google to help find the correct information?

Thanks a lot!
 
Can you be more specific for F,ci,y? I don't think there is a general solution for your problem.
 
Can you be more specific for F,ci,y? I don't think there is a general solution for your problem.

Can I ask if it would it really matter what the variables are, or that there isn't a general solution? I'm really looking for how to even approach this problem, yea? Not necessarily the exact answer laid out.
 
from my knowledge, it is difficult to solve such kind equation even F, Ci , y and t are given.
 
I have a little equation for which I need to solve for r. The problem I'm having is that I don't remember the techniques that can be used to do this, as the equation contains a summation. I spent some time on Google and in my old text books, but I haven't found anything yet. This is part of my equation:

The "(i=0 E y)" part is the Sigma notation.

F = (i=0 E y) Ci(1 + r)(t-i)
Do you mean \(\displaystyle F= \sum_{i= 0}^y C_i (1+ r)^{t- i}\)
That will be a "t" degree polynomial. There is no general formula for solving a polynomial equation of degree higher than 4.

I want to solve for r, with F, Ci, t, and y all on the other side of the equation. Can anyone help me with where I should begin with this? What the steps would look like, or what keywords I can use in Google to help find the correct information?

Thanks a lot!
 
If Ci = Constant = K

Then it becomes a geometric series and we can have a solution.
 
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