Solve the equation on the interval

dwlniles

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Dec 5, 2010
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Solve the equation on the interval 0 ? ? < 2pi
2 sin ? + 6 = 7

This is what I have done so far:

2 sin ? + 6 = 7
2 sin ? = 1
sin ? = 1/2

This is where I get stuck....

I know the interval of ? = pi/6, 5pi/6

I'm just not sure how how you figure that out? Where does the pi/6, 5pi/6 come from?
 
To get the first quadrant angle, look at a 30, 60 , 90 triangle and remember that sin x is opposite/hypotenuse.

Sine is also positive in the second quadrant. To get the second quadrant angle you take π\displaystyle \pi minus the first quadrant angle.
 
As an aside, may I show a silly mnemonic used to remember the quadrants where the trig functions are positive.

A Smart Trig Class.

Which corresponds to All Sine Tangent Cosine.
 
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