solving 2k^2 = 21k - 49: Is k(2+7)(7+3) correct?

jenzbears said:
2k^2 = 21k - 49
The first step (as they covered extensively in class) for solving a quadratic is to get "(quadratic) = 0". So your first step should be to move the 21k and the 49 to the left-hand side.

Then apply whatever methods you learned (the Quadratic Formula, completing the square, etc) to solving the equation.

jenzbears said:
k(2+7)(7 +3)
is this even close
Um... "Is this even close" to what...? It's not even related to the exercise, other than having the same variable. And "140k" obviously isn't a solution to the equation! :shock:

Please reply with clarification, showing your steps and reasoning, and using complete sentences so we can figure out what you mean. Thank you! :D

Eliz.
 
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