pcpolivick
New member
- Joined
- Oct 8, 2007
- Messages
- 4
Here is the question
A person cuts a rope into 2 pieces that are equal in length. The first piece is 4 times the length of the person's forearm minus 1 inch. The second piece is 3 times the length of tdhe person's forearm plus 15 inches.
Solve algebraically and graphically. X is person's forearm
I have
4x-1=3x+15
4x-3x=15+1
x=16
4(16)-1=63
3(16)+15=63
63 is the length of each piece of rope
Is this correct and if so how do I solve it graphically?
thanks it's been a while since I done math
A person cuts a rope into 2 pieces that are equal in length. The first piece is 4 times the length of the person's forearm minus 1 inch. The second piece is 3 times the length of tdhe person's forearm plus 15 inches.
Solve algebraically and graphically. X is person's forearm
I have
4x-1=3x+15
4x-3x=15+1
x=16
4(16)-1=63
3(16)+15=63
63 is the length of each piece of rope
Is this correct and if so how do I solve it graphically?
thanks it's been a while since I done math