T twohaha New member Joined Apr 7, 2012 Messages 18 Jun 17, 2012 #1 Find x for log(base989/942) (((79x)/90) + 1) = x I can't seem to extract the 1 from the logarithm...
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Jun 17, 2012 #3 Hello, twohaha! \(\displaystyle \text{Solve for }x\!:\;\;\log_{\frac{989}{942}} \left(\dfrac{79x}{90} + 1\right) \:=\: x\) Click to expand... It cannot be solved algebraically. It is a transcendental equation. It has an \(\displaystyle x\) "inside" a transcendental function (log) and "outside", too. Other examples are: .\(\displaystyle \begin{Bmatrix} \sin x \:= \: x \\ 3^x \:=\: x \\ \tan^{\text{-}1}x \:= \: x \end{Bmatrix}\)
Hello, twohaha! \(\displaystyle \text{Solve for }x\!:\;\;\log_{\frac{989}{942}} \left(\dfrac{79x}{90} + 1\right) \:=\: x\) Click to expand... It cannot be solved algebraically. It is a transcendental equation. It has an \(\displaystyle x\) "inside" a transcendental function (log) and "outside", too. Other examples are: .\(\displaystyle \begin{Bmatrix} \sin x \:= \: x \\ 3^x \:=\: x \\ \tan^{\text{-}1}x \:= \: x \end{Bmatrix}\)
T twohaha New member Joined Apr 7, 2012 Messages 18 Jun 17, 2012 #4 Thanks! So I'll have to graph the two functions in order to find x...