Elena Baby
New member
- Joined
- Dec 12, 2019
- Messages
- 19
Here is the problem:
I divided both sides by: Sin^2(X) and here is what I got:
I found the other public answer of the homogenous part which equals to y2=x
From what I know, I should solve the private answer of the non-homogenous part using the Lagrange method.
So:Yg = v1y1+v2y2.
I found out that v2 equals x,but when I tried finding v1, here is what I got:
Do you think I made any mistakes? If not, how can I solve this integral? Thank you for helping!
I divided both sides by: Sin^2(X) and here is what I got:
I found the other public answer of the homogenous part which equals to y2=x
From what I know, I should solve the private answer of the non-homogenous part using the Lagrange method.
So:Yg = v1y1+v2y2.
I found out that v2 equals x,but when I tried finding v1, here is what I got:
Do you think I made any mistakes? If not, how can I solve this integral? Thank you for helping!