.Hi,
I have two equations, which I am not sure how to solve. If anyone could help, I would be most grateful.
Thank You.
1. Solve 2lnx = lnx, x = 0 → ln(x2) = ln(x) .... continue
2. Solve a(b^4x-3) = b^2x a Is this problem a(b4x-3) = b2x * a or something else??
.Hi,
I have two equations, which I am not sure how to solve. If anyone could help, I would be most grateful.
Thank You.
1. Solve 2lnx = lnx, x = 0 \(\displaystyle \ \ \ \ \) This is not one equation. The part "x = 0" is not correct. Maybe it was meant to be "x > 0."
2. Solve a(b^4x-3) = b^2x a \(\displaystyle \ \ \ \ \) As was already being asked about, you have at least one error/typo here.
There are three easy concepts involved in solving this equation.Thanks for the help with the first equation. I used log and solved it.
Solve a(b^4x-3) = b^2x a As was already being asked about, you have at least one error/typo here.
This is
![]()