P panda125 New member Joined Oct 1, 2010 Messages 13 Nov 16, 2010 #1 (18)/(x-4)=1+(20)/(x+4) Hi, Not really sure how to do this problem at all can some one give me a hand here please
(18)/(x-4)=1+(20)/(x+4) Hi, Not really sure how to do this problem at all can some one give me a hand here please
M masters Full Member Joined Mar 30, 2007 Messages 378 Nov 16, 2010 #2 panda125 said: (18)/(x-4)=1+(20)/(x+4) Hi, Not really sure how to do this problem at all can some one give me a hand here please Click to expand... Hi panda125, If I'm reading this correctly you have: \(\displaystyle \frac{18}{x-4}=1+\frac{20}{x+4}\) First, multiply all terms by (x - 4)(x +4). This will yield: \(\displaystyle 18(x+4)=1(x-4)(x+4)+20(x-4)\) Expanding, we arrive at: \(\displaystyle 18x+72=x^2-16+20x-80\) Combining terms and stuff: \(\displaystyle x^2+2x-168=0\) Factor to find your two value for x.
panda125 said: (18)/(x-4)=1+(20)/(x+4) Hi, Not really sure how to do this problem at all can some one give me a hand here please Click to expand... Hi panda125, If I'm reading this correctly you have: \(\displaystyle \frac{18}{x-4}=1+\frac{20}{x+4}\) First, multiply all terms by (x - 4)(x +4). This will yield: \(\displaystyle 18(x+4)=1(x-4)(x+4)+20(x-4)\) Expanding, we arrive at: \(\displaystyle 18x+72=x^2-16+20x-80\) Combining terms and stuff: \(\displaystyle x^2+2x-168=0\) Factor to find your two value for x.
