Solving Limit at infinity with radicals (without L'hopital): sqrt[3x^5-2x] - sqrt[3x^

[AlexandraMarie112]

Limx--->positive infinity sqrt(3x⁵-2x) - sqrt(3x⁵-7x)

I have no clue how to solve this. At first, I rationalized it , then divided the top and bottom by x⁵​ , but the answer I got was wrong.

 

[stapel]

Limx--->positive infinity sqrt(3x⁵-2x) - sqrt(3x⁵-7x)

I have no clue how to solve this. At first, I rationalized it , then divided the top and bottom by x⁵​ , but the answer I got was wrong.

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