Solving Linear Equations

Petenerd

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May 13, 2009
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Solve for y in terms of x.

1. 2(x - y) = -x + 10

2. 7y - x - 1=y - (2x + 1)

Find the value that corresponds to each value of x.

1. 5 - y= \(\displaystyle \frac 1 2\)x, if x =12.

Solve for y in terms of x. Find four solutions of each equations. [sup:195h1tri](How can I do that?)[/sup:195h1tri]

1. x + 2y = -5

Please teach me how to do the problems.
 
Petenerd said:
Find the value that corresponds to each value of x.
To learn how to evaluate, try here.

Petenerd said:
Solve for y in terms of x.
First, you'll need to learn how to solve linear equations. Then, to learn how to solve literal equations, try here.

Petenerd said:
Find four solutions of each equations.
To learn how to plug x-values in and get y-values out (with the x,y-pair being a "solution"), try here.
 
Solve for y in terms of x.

1. 2(x - y) = -x + 10

To solve for y in terms of x:

y on one side = x on the other side.


To solve for x in terms of y:

x on one side = y on the other.


For this question, use the distributive rule to remove the parentheses as your first step.

See this link below to learn about the distributive rule:

http://www.themathpage.com/alg/distributive-rule.htm

Back to your question.

After applying the distributive rule on the left side, we get the following equation:

2x - 2y = -x + 10

Adding x to both sides we get:

2x + x - 2y = 10

We now combine like terms on the left side and get:

3x - 2y = 10

Subtracting 3x from both sides we get:

-2y = -3x + 10

Lastly, we divide both sides by -2 to isolate y. By the way, -2 (in this case) is called the coefficient of y.

y = (-3x + 10)/-2

y = (3x/2) - 5

You can now see that y is written in term of x.
 
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