Solving log (b^2+2) base 6 + log 2 base 6 = 2, etc

[bluegirl]

I am very confused about these logarithmic equations I have to do. My teacher gave us some examples, but they look nothing like the ones he assignmend us to do.

1. log m base 5 = 1/3 log 125 base 5

2. log y = 1/4 log 16+1/2 log 49

3. log (b^2+2) base 6 + log 2 base 6 = 2

I have no idea how to do these problems; I am sooo confused! I think that for #3, you would use the Quotient Property of Logarithms, but I'm not sure.

 

[tkhunny]

Hints:

log 125 base 5 = 3 Why?

(1/4) log(16) = log(16^(1/4)) = log(2)

(1/2) log(49) = log(49^(1/2)) = log(7)