Solving Logarithm with table - A new thread has been created to continue discussion

Status
Not open for further replies.

chijioke

Full Member
Joined
Jul 27, 2022
Messages
377
I need help with this:




Evaluate the following by the use of four-figure table.\displaystyle \text{Evaluate the following by the use of four-figure table.}





a. 3.0253759.44\displaystyle a.~ 3.025^3 - \sqrt[4]{759.4}





b. 118.634.9528371964\displaystyle b. ~\frac{118.6}{34.95} - \frac{2837}{1964}





c. 2.8743+62.87436\displaystyle c. ~\frac{2.874^3+6}{2.874^3-6}





d. 2.9083+248.45\displaystyle d. ~2.908^3 + \sqrt[5]{248.4}





e. 13013033\displaystyle e. ~\sqrt[3]{130-\sqrt[3]{130}}





f. 11.65×91.2111.652\displaystyle f. ~11.65 × 91.21-11.65^2





g. 1.214+3.235\displaystyle g. ~\sqrt[5]{1.21^4+3.2^3}





l am having difficulty when it comes to working with problems involving addition and subtractions.




I have no problem working with these ones below because the operations do not involve addition and subtraction. Please take a look at them:




i. 173.8×14.722.613\displaystyle i. ~\sqrt{\frac{173.8×14.7^2}{2.61^3}}





ii. 42.79×0.61548.737×25.61\displaystyle ii. ~\frac{42.79×\sqrt{0.6154}}{8.737×25.61}





iii. (565×0.0536249.1)23\displaystyle iii. ~\sqrt[3]{\left(\frac{565×0.0536}{249.1}\right)^2}




solutions





i.)i. 173.8×14.722.613\displaystyle i. ~\sqrt{\frac{173.8×14.7^2}{2.61^3}}





No.Log173.82.240014.721.1673×2 =2.3346173.8×14.722.2400 +2.3346 4.57462.6130.4166×3 =1.2499173.8×14.722.6134.5746 1.2499 = 3.3247173.8×14.722.6133.3247÷2 =1.6624 antilog of 1.662445.96\begin{array}{|l|r|} \text{No.} & \text{Log} \\ \hline 173.8 & 2.2400 \\ \hline 14.7^2 & 1.1673 × 2 \\ \hline ~ & = 2.3346 \\ \hline 173.8 × 14.7^2 & 2.2400 \\ ~ & + 2.3346 \\ ~ & \overline{4.5746} \\ \hline 2.61^3 & 0.4166 × 3 \\ \hline ~ & = 1.2499 \\ \hline \frac{173.8 × 14.7^2}{2.61^3} & 4.5746 \\ ~ & -1.2499 \\ ~ & =\\ \hline ~ & 3.3247 \\ \hline \sqrt{\frac{173.8 × 14.7^2}{2.61^3}} & 3.3247 ÷ 2 \\ ~ & = 1.6624 \\ ~ & \text{antilog of} \\ ~ & 1.6624 \bumpeq 45.96 \\ \end{array}
173.8×14.722.613=45.96\displaystyle \sqrt{\frac{173.8×14.7^2}{2.61^3}}=45.96



ii. 42.79×0.61548.737×25.61\displaystyle ii. ~\frac{42.79×\sqrt{0.6154}}{8.737×25.61}





No.Log 42.791.63131.613130.6154121ˉ.7892÷2  (1ˉ+0.7892)÷2  (2ˉ+0.7892)÷2+ (1ˉ+0.8946)1ˉ.8946  1.52598.7370.941325.61+1.40842.34970.15051ˉ.1762 \begin{array}{|l|r|r|} \text{No.} & \text{Log} & ~ \\ \hline 42.79 & 1.6313 & 1.61313 \\ 0.6154^\frac{1}{2} & \bar{1}.7892 ÷ 2 & ~ \\ ~ & (\bar{1} + 0.7892) ÷ 2 & ~ \\ ~ & (\bar{2} + 0.7892) ÷ 2 & + \\ ~ & (\bar{1} + 0.8946) & \bar{1}.8946 \\ ~ & ~ & \overline{1.5259} \\ 8.737 & 0.9413 & - \\ 25.61 & +1.4084 & 2.3497 \\ \hline 0.1505 & \bar{1}.1762 & ~ \\ \hline \end{array}




 42.79×0.61548.737×25.61=0.1501\displaystyle ~\frac{42.79×\sqrt{0.6154}}{8.737×25.61} = 0.1501




iii. (565×0.0536249.1)23\displaystyle iii. ~\sqrt[3]{\left(\frac{565×0.0536}{249.1}\right)^2}




NumberLogarithm5652.75200.05362ˉ.7292565×0.05361.4812249.12.3964565×0.0536249.11ˉ.0848(565×0.0536249.1)21ˉ.0848×2=2ˉ.1696(565×0.0536249.1)23=13(2ˉ.1696)=13(3ˉ+1.1696) =1ˉ.389 86 1ˉ.3899\begin{array}{|l|r|} \text{Number} & \text{Logarithm} \\ \hline 565 & 2.7520 \\ 0.0536 & \bar{2}.7292 \\ 565 × 0.0536 & \overline{1.4812} \\ 249.1 & 2.3964 \\ \frac{565×0.0536}{249.1} & \overline{\bar{1}.0848} \\ \left(\frac{565×0.0536}{249.1}\right)^2 & \bar{1}.0848 × 2 = \bar{2}.1696 \\ \sqrt[3]{\left(\frac{565×0.0536}{249.1}\right)^2} & = \frac{1}{3}(\bar{2}.1696)=\frac{1}{3}(\bar{3} + 1.1696) \\ ~ & = \bar{1}.389~86 \\ ~ & \bumpeq{\bar{1}.3899} \end{array}


iii. (565×0.0536249.1)23\displaystyle iii. ~\sqrt[3]{\left(\frac{565×0.0536}{249.1}\right)^2} =antilog of 1ˉ.3899\displaystyle = \text{antilog of}~\bar{1}.3899



=101×2.454\displaystyle = 10^{-1} × 2.454



=0.2454\displaystyle = 0.2454



=0.245(3s.f)\displaystyle = 0.245 (3 \text{s.f})


I was able to solve i, ii and iii because there was no addition subtraction involved. Now let me take a few shots at some of the problems involving subtraction and addition.


s1. 2.8808312.88083+1\displaystyle s1.~ \frac{2.8808^3-1}{2.8808^3+1}


s2. 7.93+2.133\displaystyle s2.~\sqrt[3]{7.9^3 + 2.1^3}


s3. 61.73238.272\displaystyle s3.~\sqrt{61.73^2 - 38.27^2}

s4. 9.5837.6333\displaystyle s4.~\sqrt[3]{9.58^3 - 7.63^3}
 
In 3.025^3 - 4th root(759.4)
Just compute the Log of each number separately.
Give it a try and post back with your work.
 
I need help with this: Evaluate the following by the use of four-figure table.\displaystyle \text{Evaluate the following by the use of four-figure table.}
a. 3.0253759.44\displaystyle a.~ 3.025^3 - \sqrt[4]{759.4}
b. 118.634.9528371964\displaystyle b. ~\frac{118.6}{34.95} - \frac{2837}{1964}
c. 2.8743+62.87436\displaystyle c. ~\frac{2.874^3+6}{2.874^3-6}
d. 2.9083+248.45\displaystyle d. ~2.908^3 + \sqrt[5]{248.4}
e. 13013033\displaystyle e. ~\sqrt[3]{130-\sqrt[3]{130}}
f. 11.65×91.2111.652\displaystyle f. ~11.65 × 91.21-11.65^2
g. 1.214+3.235\displaystyle g. ~\sqrt[5]{1.21^4+3.2^3}
Hi chijioke. Did you post exercises (a) through (g) above as examples only? I'm not sure where you'd like to begin.

Now let me take a few shots at some of the problems involving subtraction and addition.
s1. 2.8808312.88083+1\displaystyle s1.~ \frac{2.8808^3-1}{2.8808^3+1}
s2. 7.93+2.133\displaystyle s2.~\sqrt[3]{7.9^3 + 2.1^3}
s3. 61.73238.272\displaystyle s3.~\sqrt{61.73^2 - 38.27^2}
s4. 9.5837.6333\displaystyle s4.~\sqrt[3]{9.58^3 - 7.63^3}
Are these the exercises you'd like help with? Have you seen any lessons, for using the four-figure table approach with expressions that include addition/subtraction? What kind of help would you like?

:)

  \;
 
I have no problem working with these ones below because the operations do not involve addition and subtraction. Please take a look at them:
i. 173.8×14.722.613\displaystyle i. ~\sqrt{\frac{173.8×14.7^2}{2.61^3}}
ii. 42.79×0.61548.737×25.61\displaystyle ii. ~\frac{42.79×\sqrt{0.6154}}{8.737×25.61}
iii. (565×0.0536249.1)23\displaystyle iii. ~\sqrt[3]{\left(\frac{565×0.0536}{249.1}\right)^2}
You're asking us to check your work on exercises (i) through (iii). Is that correct?

:)

  \;
 
Am not through with my typing yet. How I wish this thread can be deleted.
 
Am not through with my typing yet. How I wish this thread can be deleted.
Just don't submit it (Post reply) until you have it right. You can see if it is right by using Preview:

1661383163724.png

Also note that you can leave your work and come back later to edit it, and submit when ready.
 
Thanks I have seen the preview button. Am going to make use of it now instead of posting and deleting continually. But come to think of it, how do I delete or just edit the number 1 thread?
 
You can only edit a post with about 20 minutes of posting it.
 
how do I delete or just edit the number 1 [post]?
After the time limit expires, you can't. When you're ready to post your revised text, you could start a new thread and ask a moderator to delete this one.

?

  \;
 
When you're ready to post your revised text, you could start a new thread and ask a moderator to delete this one.

?

  \;
That's is what I will do. But how do I get the moderator to delete the old thread when am done with the revised one?
 
how do I get the moderator to delete the old thread when am done with the revised one?

ask a moderator to delete this one
The forum allows you to send private messages to other members, including moderators. Click a user name, to open their profile page. Use the 'Start conversation' button.

:)

  \;
 
Status
Not open for further replies.
Top