Hooty143 said:
The problem is
tan(x)sin(x)-sin(x)=0
0°?x<360°
the only step I know is
tan(x)sin(x)=sin(x)
What do I use for x?
Ummmm....you are supposed to FIND value(s) for x which will make the equation true.
You could FACTOR the left side of
tan x sin x - sin x = 0
The two terms have a common factor of sin x; remove that common factor and you'll have
sin x (tan x - 1) = 0
Now, remember the "Zero Product Property" from algebra? If a*b = 0, then either a = 0 or b = 0.
If sin x (tan x - 1) = 0, then
sin x = 0
OR
tan x - 1 = 0
Now, you have two equations....I'll help you with ONE of them.
tan x - 1 = 0
Add 1 to both sides, and you have
tan x = 1
In the interval 0
< x
< 360, when is tan x = 1? I believe if you look at the unit circle, you'll find that tan x = 1 for x = 45[sup:36i37edw]o[/sup:36i37edw] and x = 225[sup:36i37edw]o[/sup:36i37edw]
So that gives you TWO solutions. Now, YOU need to look at the other equation, sin x = 0, and find the values of x in the required interval for which sin x = 0.
