solving Quadratic Equations by Factoring

x^2 +7x = -12

x^2 +7x +12 = 0

now it is in the standard form to be solved.
 
need to understand what you have typed.....

(6x + 5)squrt =2

if this is (6x + 5) ^ 2 = 2

then
(6x + 5) (6x + 5) = 2

36x^2 + 60x + 25 = 2

36x^2 +60x +23 = 0

back as a quadratic to solve.
 
using the Square Root Property

if X^2 = a, then X =(minusplus)sqrt a for all reall numbers a.

I hope you can understand that.

with this i work the problem like this

(6x + 5)^2 =2

(6x +5)= minusplus sqrt2

6x = 5 minusplus sqrt2
x =5 minusplus sqrt2/6

I hope you can understand all that.
 
latresa31s said:
using the Square Root Property
if X^2 = a, then X =(minusplus)sqrt a for all reall numbers a.
I hope you can understand that.
with this i work the problem like this
(6x + 5)^2 =2
(6x +5)= minusplus sqrt2
6x = 5 minusplus sqrt2
x =5 minusplus sqrt2/6
I hope you can understand all that.
Click to expand...
Boy oh boy, Lastress, you'll have to learn to be clearer and more careful...
you first posted this: (6x + 5)squrt =2 : makes no sense;
then apm asked you if you meant (6x + 5)^2 = 2:
why didn't you simply answer : YES!
Remember that ^2 means SQUARED.
From now on, show x squared as x^2 and square root of x as sqrt(x).
If you don't, your posts will be accidentally deleted :wink:

Let's go over what you did:
(6x + 5)^2 =2
(6x +5)= minusplus sqrt2; show like this: 6x + 5 = +- sqrt(2)
6x = 5 minusplus sqrt2; NO! : 6x = -5 +- sqrt(2)
x =5 minusplus sqrt2/6; x = [-5 +- sqrt(2)] / 6

If a + b = c, then a = c - b
or if a - b = c, then a = c + b : remember that!
What grade are you in?
 
I am a not in a grade I am a student of Kaplun University online and this is my very first algebra class.

I just need help with this problem

(6x + 5)^2 = 2

using the spuare root property.
 
You must log in or register to reply here.
Top