Please show us what you have tried and exactly where you are stuck.View attachment 22453
I have been trying to solve this derivative for a couple hours now to no avail! Any help would be appreciated.
Unfortunately it gives me the wrong answerWhat you always can try is:
derivative of (ln(x))^sec(x) - Wolfram|Alpha
Wolfram|Alpha brings expert-level knowledge and capabilities to the broadest possible range of people—spanning all professions and education levels.www.wolframalpha.com
Does that mean that you know the answer?Unfortunately it gives me the wrong answer
Please write (post) the corrected version you propose.To OP, Prof Halls made a slight mistake. Starting with the 2nd line where ever you see ln(ln(x)) it should be ln(x).
To OP, Prof Halls made a slight mistake. Starting with the 2nd line where ever you see ln(ln(x)) it should be ln(x).
Differentiating that, \(\displaystyle \frac{1}{y}\frac{dy}{dx}= [sec(x)tan(x)]ln(ln(x))+ sec(x)\frac{1}{ln(ln(x))}\frac{1}{x}\)