M math. New member Joined Mar 17, 2013 Messages 18 Mar 24, 2013 #1 The problem: sin 2a = 1, 0<=a<2pi I'm confused as to what the two before the a means... Its not sin2a, but two before the a itself.
The problem: sin 2a = 1, 0<=a<2pi I'm confused as to what the two before the a means... Its not sin2a, but two before the a itself.
D Deleted member 4993 Guest Mar 24, 2013 #2 math. said: The problem: sin 2a = 1, 0<=a<2pi I'm confused as to what the two before the a means... Its not sin2a, but two before the a itself. Click to expand... It is double angle (2*a) Thus if 2a = 60° → a = 30°
math. said: The problem: sin 2a = 1, 0<=a<2pi I'm confused as to what the two before the a means... Its not sin2a, but two before the a itself. Click to expand... It is double angle (2*a) Thus if 2a = 60° → a = 30°
